Home » How to add/remove an element to/from the array in bash?

How to add/remove an element to/from the array in bash?

Solutons:


To add an element to the beginning of an array use.

arr=("new_element" "${arr[@]}")

Generally, you would do.

arr=("new_element1" "new_element2" "..." "new_elementN" "${arr[@]}")

To add an element to the end of an array use.

arr=( "${arr[@]}" "new_element" )

Or instead

arr+=( "new_element" )

Generally, you would do.

arr=( "${arr[@]}" "new_element1" "new_element2" "..." "new_elementN") #Or
arr+=( "new_element1" "new_element2" "..." "new_elementN" )

To add an element to specific index of an array use.

Let’s say we want to add an element to the position of Index2 arr[2], we would actually do merge on below sub-arrays:

  1. Get all elements before Index position2 arr[0] and arr[1];
  2. Add an element to the array;
  3. Get all elements with Index position2 to the last arr[2], arr[3], ….

    arr=( "${arr[@]:0:2}" "new_element" "${arr[@]:2}" )
    

Removing an element from the array

In addition to removing an element from an array (let’s say element #3), we need to concatenate two sub-arrays. The first sub-array will hold the elements before element #3 and the second sub-array will contain the elements after element #3.

arr=( "${arr[@]:0:2}" "${arr[@]:3}" )
  • ${arr[@]:0:2} will get two elements arr[0] and arr[1] starts from the beginning of the array.
  • ${arr[@]:3} will get all elements from index3 arr[3] to the last.

    one possible handy way to re-build the arr excluding element#3 (arr[2]) from that:

    del_element=3; arr=( "${arr[@]:0:$((del_element-1))}" "${arr[@]:$del_element}" )
    

    specify which element you want to exclude in del_element=.

Another possibility to remove an element is

  1. Using unset (actually assign ‘null’ value to the element)

    unset -v 'arr[2]'
    
  2. Use replace pattern if you know the value of your array elements to truncate their value (replace with empty string).

    arr=( "${arr[@]/PATTERN/}" )
    

Print the array

printf '%sn' "${arr[@]}"

Note that arrays in bash (copied from ksh) are rather associative arrays (with keys limited to positive integers also called sparse arrays).

a=(newvalue "$a[@]")

would make a new $a array with newvalue as ${a[0]} and the elements of the original array appended in the numerical order of their key with keys 1, 2…

For instance, if you had:

bash-4.4$ typeset -p a
declare -a a=([0]="foo" [12]="bar")
bash-4.4$ a=(newvalue "${a[@]}")
bash-4.4$ typeset -p a
declare -a a=([0]="newvalue" [1]="foo" [2]="bar")

That explains why there’s no builtin operator for that.

If you wanted to insert the newvalue as ${a[0]} and shift all the other keys by one, you’d need a temporary array:

b=newvalue
for k in "${!a[@]}"; do
  b[k+1]=${a[k]}
done
unset a
for k in "${!b[@]}"; do
  a[k]=${b[k]}
done
unset b

Shells like zsh or yash that have normal arrays have operators for that:

  • zsh:

      a[1,0]=newvalue
    

(also works for prepending strings to scalar variables)

  • yash:

      array -i a 0 newvalue
    

Create an Indexed Array:

$ declare -a A
$ declare -p A

declare -a A

Add some elements to the array:

$ A+=(foo)
$ A+=(bar)
$ A+=("baz quux")
$ declare -p A

declare -a A=([0]=”foo” [1]=”bar” [2]=”baz quux”)

Remove the middle element, making it a Sparse Indexed array:

$ unset A[1]
$ declare -p A

declare -a A=([0]=”foo” [2]=”baz quux”)

Remove the last element from the Sparse Indexed Array:

$ unset A[-1]
$ declare -p A

declare -a A=([0]=”foo”)

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