Home » How to print all lines after a match up to the end of the file?

How to print all lines after a match up to the end of the file?


In practice, I’d probably use Aet3miirah’s answer most of the time, and alexey’s answer is wonderful for navigating through the lines (also, it works with less). OTOH, I really like another approach (which is kind of the reversed Gilles’ answer):

sed -n '/dog 123 4335/,$p'

When called with the -n flag, sed does not print by default the lines it processes anymore. Then we use a 2-address form that says to apply a command from the line matching /dog 123 4335/ until the end of the file (represented by $). The command in question is p, which prints the current line. So, this means “print all lines from the one matching /dog 123 4335/ until the end.”

Assuming you want to match the whole line with your pattern, with GNU sed, this works:

sed -n '/^dog 123 4335$/ { :a; n; p; ba; }' infile

Standard equivalent:

sed -ne '/^dog 123 4335$/{:a' -e 'n;p;ba' -e '}' infile

With the following input (infile):

cat 13123 23424 
deer 2131 213132
bear 2313 21313
dog 123 4335
cat 13123 23424 
deer 2131 213132
bear 2313 21313

The output is:

cat 13123 23424 
deer 2131 213132
bear 2313 21313


  • /^dog 123 4335$/ searches for the desired pattern.
  • :a; n; p; ba; is a loop that fetches a new line from input (n), prints it (p), and branches back to label a :a; ...; ba;.


Here’s an answer that comes closer to your needs, i.e. pattern in file2, grepping from file1:

tail -n +$(( 1 + $(grep -m1 -n -f file2 file1 | cut -d: -f1) )) file1

The embedded grep and cut find the first line containing a pattern from file2, this line number plus one is passed on to tail, the plus one is there to skip the line with the pattern.

If you want to start from the last match instead of the first match it would be:

tail -n +$(( 1 + $(grep -n -f file2 file1 | tail -n1 | cut -d: -f1) )) file1

Note that not all versions of tail support the plus-notation.

If you have a reasonably short file grep alone might work:

grep -A5000 -m1 -e 'dog 123 4335' animals.txt

5000 is just my guess at “reasonably short”, as grep finds the first match and outputs it together with the next 5000 lines (the file doesn’t need to have that many). If you don’t want the match itself you’ll need to cut it off, e.g.

grep -A5000 -m1 -e 'dog 123 4335' animals.txt | tail -n+2

If you do not want the first, but the last match as delimiter you could use this:

tac animals.txt | sed -e '/dog 123 4335/q' | tac

This line reads animals.txt in reverse order of lines and outputs up to and including the line with dog 123 4335 and then reverses again to restore proper order.

Again, if you don’t need the match in the result, append tail. (You could also complicate the sed expression to discard its buffer before quitting.)

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