Home » Number of Nearest ‘True’ in a matrix or list of list

Number of Nearest ‘True’ in a matrix or list of list


Definitely not the best way to do it, but it’s one that works:

import numpy as np

mas1 = np.array([[True, False,  True],
       [ False,  True,  True],
       [ False,  True,  False]])

mas_answer = np.ndarray(shape=mas1.shape)

for i in range(mas1.shape[0]):
    for j in range(mas1.shape[1]):
        close_elt = []
        if i >= 1:

        if j >= 1:

        if i >= 1 and j >= 1:



        mas_answer[i,j] = close_elt.count(True)

# Ouput:
array([[1., 4., 2.],
       [3., 4., 3.],
       [2., 2., 3.]])

You probably can try this Python approach: (just comment out the print statements)
# filename – my_neighbors.py

from itertools import product

coordinates = list(product(range(3), range(3)))

matrix =  [['A', 'B', 'A'], 
           ['B', 'A', 'A'],
           ['B', 'A', 'B']]

# Number of Nearest 'True' in a matrix or list of list

         #   [[1, 4, 2],
         #    [3, 4, 3],
         #    [2, 2, 3]]

def neighbors(grid, r, c):
    vals = sum((row[c -(c>0): c+2]
                for row in grid[r -(r>0):r+2]), [])
    vals.remove(grid[r][c])      # rm itself.
    return list(vals)            # return all neighbors

new_matrix = [[0 for c in range(3)] for r in range(3)]

for r, c in coordinates:
    print(f' {r}{c} -> all neighbors: ')
    print(f' t  {neighbors(matrix, r, c)} ')
    neighs = neighbors(matrix, r, c)
    summ   = neighs.count('A')
    print(f' t t summ: {summ} ')
    new_matrix[r][c] = summ


# [[1, 4, 2], [3, 4, 3], [2, 2, 3]]

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