Home » Panagram python code [closed]

Panagram python code [closed]

Solutons:


import string
def isPanagram(sentence):
    alphabet = string.lowercase[:26]   # list of letters a-z
    return all(letter in sentence.lower() for letter in alphabet)
  1. The function all will return true if all elements in a list are true

  2. The list comprehension inside goes over all the letters of alphabet and checks if they are in your sentence after it has been changed to all lowercase with .lower().

Create a list of all the letters in the alphabet. Once that is done, use a for loop which uses a try/except method to check if i in (yourlist) == True. If at any point it passes a ValueError exception then you can be sure your string is not a pangram.

here is a sample code:

def isPanagram(arg_str):
    alphabetList = [ chr(alphababet) for alphababet in xrange(65,91)] # create a list of all english letter in uppercase
    upperString = arg_str.upper()       #cast all alphabet to uppercase in the give string
    result = True                       #unless a alphabet is missing we will return true, so initializing to true
    for alph in alphabetList:           #for each alphabet character
        result = result * (alph in upperString) #multiply result with whether this alphabet exists or not (becomes zero if any not found)
        continue
    return result

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