return statement in c ??? why this function always returning 20?


You have a problem in your code. Change




This is done because scanf expects an argument of type int* but you provide argument arr[i] which is of type int. Also add a check that ends the program if user inputs a number which is greater than 10 for the first scanf.

There can be two reasons.

Case 1 [Much likely for _always_]

Simple. Because your if(arr[i]==n) condition is not met, and i<m became false. It came out of for() loop and hence, return 20.

case 2 [Less likely for _always_]

By chance, the value of n is present at the 21st location [index 20] in the input array.

Apart from the coding aspect, did you understand what’s the logical purpose of this function? If not, begin with that. It searches for a specific value in an array of given length, and if no element of the array matches that value, it returns 20.

Now analyze your case, based on your input.


After seeing the complete code, as Mr. CoolGuy has pointed out, use


Just for more reference, you can look at Chapter, paragraph 12 , %d format specifier, which goes like

… The corresponding argument shall be a pointer to signed integer.

In your code, arr[i] is of type int. What you need is a int *, i.e., &arr[i].

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