Home » What is the regex pattern for datetime (2008-09-01 12:35:45 )?

What is the regex pattern for datetime (2008-09-01 12:35:45 )?


@Espo: I just have to say that regex is incredible. I’d hate to have to write the code that did something useful with the matches, such as if you wanted to actually find out what date and time the user typed.

It seems like Tom’s solution would be more tenable, as it is about a zillion times simpler and with the addition of some parentheses you can easily get at the values the user typed:

(d{4})-(d{2})-(d{2}) (d{2}):(d{2}):(d{2})

If you’re using perl, then you can get the values out with something like this:

$year = $1;
$month = $2;
$day = $3;
$hour = $4;
$minute = $5;
$second = $6;

Other languages will have a similar capability. Note that you will need to make some minor mods to the regex if you want to accept values such as single-digit months.

A simple version that will work for the format mentioned, but not all the others as per @Espos:

(d{4}-d{2}-d{2} d{2}:d{2}:d{2}) 



This RE validates both dates and/or
times patterns. Days in Feb. are also
validated for Leap years. Dates: in
dd/mm/yyyy or d/m/yy format between
1/1/1600 – 31/12/9999. Leading zeroes
are optional. Date separators can be
either matching dashes(-), slashes(/)
or periods(.) Times: in the hh:MM:ss
AM/PM 12 hour format (12:00 AM –
11:59:59 PM) or hh:MM:ss military time
format (00:00:00 – 23:59:59). The 12
hour time format: 1) may have a
leading zero for the hour. 2) Minutes
and seconds are optional for the 12
hour format 3) AM or PM is required
and case sensitive. Military time 1)
must have a leading zero for all hours
less than 10. 2) Minutes are
manditory. 3) seconds are optional.
Datetimes: combination of the above
formats. A date first then a time
separated by a space. ex) dd/mm/yyyy

Edit: Make sure you copy the RegEx from the regexlib.com website as StackOverflow sometimes removes/destroys special chars.

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